使用 for 循环出列表元素，并逐以放到新的列表中：

#!/usr/bin/python
# -*- coding: UTF-8 -*-

l = [1,2,3,4,5]
p = []
for i in range(len(l)):    
    p.append(l[i])
print p

参考方法：

#!/usr/bin/env python
# -*- coding: UTF-8 -*-

"""将一个列表的数据复制到另一个列表中。"""

"""
使用[:]

"""

a = [1,2,3]
b = a[:]
print b       # 将a的数据赋值给b 当a的数值发生改变时b不变
[1, 2, 3]
a = [1,2,3]
b = a
print b       # 将a的地址赋值给b 当a的数值发生改变时b随之改变
[1, 2, 3]
a = [1,2,3]
b = a[:]
print b
a[0] = 0
print a        # 将a的数据赋值给b 当a的数值发生改变时b不变
print b
[1, 2, 3]
[0, 2, 3]
[1, 2, 3]
a = [1,2,3]
b = a
print b
a[0] = 0
print a         # 将a的地址赋值给b 当a的数值发生改变时b随之改变
print b

比较暴力的一个方法，前面大佬们没提到

# -*- coding: UTF-8 -*-
#讲列表复制到另一个列表里
a = [1,2,3,4,5,6,7,8,9]
b = a*1
print(b)

补充一个深拷贝与浅拷贝的问题

>>> import copy
>>> a = [1,2,3,4,5]
>>> b = ["A","B",a]
>>> #浅拷贝
>>> c = b[:]
>>> c
['A', 'B', [1, 2, 3, 4, 5]]
>>> a[0] = 11
>>> c
['A', 'B', [11, 2, 3, 4, 5]]
>>> #此时a变化c跟着变化
>>> #深拷贝
>>> c = copy.deepcopy(b)
>>> c
['A', 'B', [11, 2, 3, 4, 5]]
>>> a[0] = 111
>>> a
[111, 2, 3, 4, 5]
>>> c
['A', 'B', [11, 2, 3, 4, 5]]
>>> #此时c中数据不受a影响
>>>